this post was submitted on 25 Feb 2024
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[–] [email protected] 1 points 1 year ago* (last edited 1 year ago)

Assuming the cost of an arbitrary house as $500,000, the density of silver as 10,490 kg/m³ and if we retain the thickness-to-diameter ratio of a $1 dollar coin (around 0.065), we need 680.27 kg ($735/kg) of silver, which, distributed to 10 silver coins, would result in each silver coin having a diameter of 50.27 cm, or 19.79 inch.