this post was submitted on 27 Jun 2024
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2/9 = 0.222... 7/9 = 0.777...
0.222... + 0.777... = 0.999... 2/9 + 7/9 = 1
0.999... = 1
No, it equals 1.
Similarly, 1/3 = 0.3333…
So 3 times 1/3 = 0.9999… but also 3/3 = 1
Another nice one:
Let x = 0.9999… (multiply both sides by 10)
10x = 9.99999… (substitute 0.9999… = x)
10x = 9 + x (subtract x from both sides)
9x = 9 (divide both sides by 9)
x = 1
My favorite thing about this argument is that not only are you right, but you can prove it with math.
Not a proof, just wrong. In the "(substitute 0.9999… = x)" step, it was only done to one side, not both (the left side would've become 9.99999), therefore wrong.
They multiplied both sides by 10.
0.9999... times 10 is 9.9999...
X times 10 is 10x.
10x is 9.9999999....
As I said, they didn't substitute on both sides, only one, thus breaking the rules around rearranging algebra. Anything you do to one side you have to do to the other.
That's the best explanation of this I've ever seen, thank you!
That's more convoluted than the 1/3, 2/3, 3/3 thing.
3/3 = 0.99999...
3/3 = 1
If somebody still wants to argue after that, don't bother.
Nah that explanation is basically using an assumption to prove itself. You need to first prove that 1/3 does in fact equal .3333... which can be done using the 'convoluted' but not so convoluted proof