Katzenmann

joined 3 months ago
[–] [email protected] 2 points 2 weeks ago

I think it should be possible with a reverse proxy. I don't see why not

[–] [email protected] 6 points 2 weeks ago

School food ruined so many things for me. I used to hate rice and gyros but they are really tasty if prepared well

[–] [email protected] 2 points 2 weeks ago

Looks like non-small lurrIb cancer to me

[–] [email protected] 4 points 2 weeks ago

Android definitely has encrypion, but it is just the user data not the programs. It you ever run mount on an android device you will see that it has lots of different partitions for that sort of stuff

[–] [email protected] 3 points 2 weeks ago (1 children)

What does wayland support mean in the context of vim? Like wayland clipboard or what?

[–] [email protected] 2 points 1 month ago (1 children)

I actually did this. It did not end up being any faster than the brute-force solution since it seems to only catch the easy cases

[–] [email protected] 36 points 1 month ago (1 children)

You're using the meme wrong. The "at home" needs to be worse than the "mom can we get?"

[–] [email protected] 4 points 1 month ago (1 children)

Weiß ja nicht. Alles was ich von Staiy mitbekommen habe ist, dass er sich oft über dinge aufregt. Aber das kann sich ja auch geändert haben

[–] [email protected] 1 points 1 month ago

Rust

Pretty happy with my solution today. I took my time today as it was a bit of a slow day and did it in Rust instead of python. Having proper Vec2 types is very nice.

Tap for spoiler

use std::{collections::HashMap, error::Error, io::Read};

use glam::{IVec2, Vec2};

fn permutations_of_size_two(antennas: &[Vec2]) -> Vec<[&Vec2; 2]> {
    let mut permutations = vec![];
    for (i, antenna) in antennas.iter().enumerate() {
        for j in 0..antennas.len() {
            if i == j {
                continue;
            }
            permutations.push([antenna, &antennas[j]])
        }
    }
    permutations
}

fn main() -> Result<(), Box<dyn Error>> {
    let mut input = String::new();
    std::io::stdin().read_to_string(&mut input)?;

    let height = input.lines().count() as i32;
    let width = input.lines().next().unwrap().len() as i32;

    let antenna_positions = input
        .lines()
        .enumerate()
        .flat_map(|(y, l)| 
            l.chars().enumerate().map(move |(x, c)| (Vec2::new(x as f32, y as f32), c))
        )
        .filter(|(_v, c)| *c != '.')
        .fold(HashMap::new(), |mut acc: HashMap<char, Vec<_>> , current| {
            acc.entry(current.1).or_default().push(current.0);
            acc
        });

    let mut antinodes = vec![];
    for (_c, antennas) in antenna_positions {
        let perms = permutations_of_size_two(&antennas);
        for [first, second] in perms {
            let mut i = 1.;
            loop {
                let antinode = (first + (second-first) * i).round();
                if (0..height).contains(&(antinode.x as i32)) &&
                    (0..width).contains(&(antinode.y as i32)) {
                        antinodes.push(antinode);
                } else {
                    break;
                }
                i += 1.;
            }
        }
    }

    let mut antinode_count = 0;
    let map = input
        .lines()
        .enumerate()
        .map(|(y, l)| 
            l.chars().enumerate().map(|(x, c)| {
                if antinodes.contains(&Vec2::new(x as f32, y as f32)) {
                    println!("({x},{y})");
                    antinode_count += 1;
                    return '#';
                }
                c
            }).collect::<String>()
        )
        .collect::<Vec<_>>()
        .join("\n");

    println!("{map}");
    println!("{antinode_count}");

    Ok(())
}

[–] [email protected] 1 points 1 month ago* (last edited 1 month ago)

My initial comment was a bit harsh, I'm sorry for that. It was meant to be a bit of a joke. Anyway here's my code. Do note that I don't do the challenges timed so I have a bit more time to name my variables accordingly. Takes 35 seconds to run on a pc with a AMD Ryzen 5 5600

import sys
from tqdm import tqdm


input = sys.stdin.read()

def all_operator_permutations(operator_count):
    if operator_count == 0:
        return [[]]

    smaller_permutations = all_operator_permutations(operator_count-1)
    return [
            *[['+', *ops] for ops in smaller_permutations],
            *[['*', *ops] for ops in smaller_permutations],
            *[['||', *ops] for ops in smaller_permutations],
            ]

def test_operators(ops, values):
    res = values.pop(0)
    for op in ops:
        match op:
            case '*':
                res *= values.pop(0)
            case '+':
                res += values.pop(0)
            case '||':
                res = int(f"{res}{values.pop(0)}")
    return res


total_calibration_result = 0

for line in tqdm(input.splitlines()[:]):
    target, *tail = line.split(':')
    target = int(target)
    values = [int(val) for val in tail[0].split()]

    all_perms = all_operator_permutations(len(values) - 1)
    ops = all_perms.pop()
    while True:
        res = test_operators(ops, values.copy())
        if res == target:
            total_calibration_result += target
            break
        if not all_perms:
            break
        ops = all_perms.pop()

print(total_calibration_result)
[–] [email protected] 1 points 1 month ago (3 children)

What a horrible way to name variables

[–] [email protected] 10 points 1 month ago (1 children)

Weil er überlebt hat

 

So with the recent drama it looks like bcachefs isn't going to stay in the kernel for too long. What do I do now? I have my root filesystem as bcachefs on multiple devices. Is it possible to migrate to btrfs or ext4?

 

Hi. Manchmal wenn ich mit meinen etwas weniger linken Freunden über Politik rede und es auf das Thema Vermögenssteuer kommt, bekomme ich "Wenn man die Reichen besteuert ziehen die weg" als Antwort.

Ich glaube nicht, dass das der Fall ist, habe allerdings nicht so richtig eine Antwort darauf. Was sagt ihr dazu?

 

Does a Kodi addon for YouTube exits, that doesn't need an API key? I don't want to create a google account. So is there an addon for Kodi that uses either yt-dlp or NewPipe Extractor to work?

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