Mathematicians will in one breath tell you they aren't fractions, then in the next tell you dz/dx = dz/dy * dy/dx
Science Memes
Welcome to c/science_memes @ Mander.xyz!
A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.
Rules
- Don't throw mud. Behave like an intellectual and remember the human.
- Keep it rooted (on topic).
- No spam.
- Infographics welcome, get schooled.
This is a science community. We use the Dawkins definition of meme.
Research Committee
Other Mander Communities
Science and Research
Biology and Life Sciences
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- !reptiles and [email protected]
Physical Sciences
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
- [email protected]
Humanities and Social Sciences
Practical and Applied Sciences
- !exercise-and [email protected]
- [email protected]
- !self [email protected]
- [email protected]
- [email protected]
- [email protected]
Memes
Miscellaneous
Have you seen a mathematician claim that? Because there's entire algebra they created just so it becomes a fraction.
Brah, chain rule & function composition.
The thing is that it's legit a fraction and d/dx actually explains what's going on under the hood. People interact with it as an operator because it's mostly looking up common derivatives and using the properties.
Take for example ∫f(x) dx
to mean "the sum (∫) of supersmall sections of x (dx) multiplied by the value of x at that point ( f(x) ). This is why there's dx at the end of all integrals.
The same way you can say that the slope at x is tiny f(x) divided by tiny x or d*f(x) / dx
or more traditionally (d/dx) * f(x)
.
clearly, d/dx simplifies to 1/x
I found math in physics to have this really fun duality of "these are rigorous rules that must be followed" and "if we make a set of edge case assumptions, we can fit the square peg in the round hole"
Also I will always treat the derivative operator as a fraction
2+2 = 5
…for sufficiently large values of 2
i was in a math class once where a physics major treated a particular variable as one because at csmic scale the value of the variable basically doesn't matter. the math professor both was and wasn't amused
If not fraction, why fraction shaped?
Derivatives started making more sense to me after I started learning their practical applications in physics class. d/dx
was too abstract when learning it in precalc, but once physics introduced d/dt
(change with respect to time t), it made derivative formulas feel more intuitive, like "velocity is the change in position with respect to time, which the derivative of position" and "acceleration is the change in velocity with respect to time, which is the derivative of velocity"
Possibly you just had to hear it more than once.
I learned it the other way around since my physics teacher was speedrunning the math sections to get to the fun physics stuff and I really got it after hearing it the second time in math class.
But yeah: it often helps to have practical examples and it doesn't get any more applicable to real life than d/dt.
Except you can kinda treat it as a fraction when dealing with differential equations
1/2 <-- not a number. Two numbers and an operator. But also a number.
In Comp-Sci, operators mean stuff like >>
, *
, /
, +
and so on. But in math, an operator is a (possibly symbollic) function, such as a derivative or matrix.
Youre not wrong, distinctively, but even in mathematics "/" is considered an operator.
https://en.m.wikipedia.org/wiki/Operation_(mathematics)
oh huh, neat. Always though of those as "operations."
It was a fraction in Leibniz’s original notation.
And it denotes an operation that gives you that fraction in operational algebra...
Instead of making it clear that d
is an operator, not a value, and thus the entire thing becomes an operator, physicists keep claiming that there's no fraction involved. I guess they like confusing people.
The world has finite precision. dx isn't a limit towards zero, it is a limit towards the smallest numerical non-zero. For physics, that's Planck, for engineers it's the least significant bit/figure. All of calculus can be generalized to arbitrary precision, and it's called discrete math. So not even mathematicians agree on this topic.
Why does using it as a fraction work just fine then? Checkmate, Maths!
This very nice Romanian lady that taught me complex plane calculus made sure to emphasize that e^j*theta was just a notation.
Then proceeded to just use it as if it was actually eulers number to the j arg. And I still don’t understand why and under what cases I can’t just assume it’s the actual thing.
Let's face it: Calculus notation is a mess. We have three different ways to notate a derivative, and they all suck.
Calculus was the only class I failed in college. It was one of those massive 200 student classes. The teacher had a thick accent and hand writing that was difficult to read. Also, I remember her using phrases like "iff" that at the time I thought was her misspelling something only to later realize it was short hand for "if and only if", so I can't imagine how many other things just blew over my head.
I retook it in a much smaller class and had a much better time.
e^𝘪θ^ is not just notation. You can graph the entire function e^x+𝘪θ^ across the whole complex domain and find that it matches up smoothly with both the version restricted to the real axis (e^x^) and the imaginary axis (e^𝘪θ^). The complete version is:
e^x+𝘪θ^ := e^x^(cos(θ) + 𝘪sin(θ))
Various proofs of this can be found on wikipeda. Since these proofs just use basic calculus, this means we didn't need to invent any new notation along the way.
I'm aware of that identity. There's a good chance I misunderstood what she said about it being just a notation.
It's not simply notation, since you can prove the identity from base principles. An alien species would be able to discover this independently.
I've seen e^{d/dx}
It legitimately IS exponentiation. Romanian lady was wrong.
It's not even a fraction, you can just cancel out the two "d"s
"d"s nuts lmao
Look it is so simple, it just acts on an uncountably infinite dimensional vector space of differentiable functions.
Having studied physics myself I'm sure physicists know what a derivative looks like.
But df/dx is a fraction, is a ratio between differential of f and standard differential of x. They both live in the tangent space TR, which is isomorphic to R.
What's not fraction is \partial f / \partial x, but likely you already know that. This is akin to how you cannot divide two vectors.
When a mathematician want to scare an physicist he only need to speak about ∞
Only the sith deal in ∞
....and Buzz Lightyear
I still don't know how I made it through those math curses at uni.
Calling them 'curses' is apt